An object of mass 3 ,kg is tied by a string o | vedclass

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(D) When the object is released from rest, its velocity is zero. Therefore, the centripetal acceleration $(a_c = v^2/r)$ is zero.The forces acting on

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$5.0$

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(D) When the object is released from rest, its velocity is zero. Therefore, the centripetal acceleration $(a_c = v^2/r)$ is zero.The forces acting on the object are its weight $(mg)$ acting vertically downwards and the tension $(T)$ in the string acting along the string.We resolve the weight $(mg)$ into two components: one along the string $(mg \cos 30^{\circ})$ and one perpendicular to the string $(mg \sin 30^{\circ})$.Since the string remains taut and the object starts from rest, the net force along the string must be zero to satisfy the condition of no radial motion at the instant of release $(T - mg \cos 30^{\circ} = 0)$.The net force acting on the object is the component perpendicular to the string, which is $F_{net} = mg \sin 30^{\circ}$.Using Newton's second law, $F_{net} = ma$, we get:$ma = mg \sin 30^{\circ}$$a = g \sin 30^{\circ}$Given $g = 10 \,ms^{-2}$ and $\sin 30^{\circ} = 0.5$:$a = 10 	imes 0.5 = 5.0 \,ms^{-2}$.

An object of mass $3 \,kg$ is tied by a string of negligible mass to a ceiling and held such that the string is taut. The object is released suddenly such that the string remains taut. Its acceleration when released is (acceleration due to gravity $= 10 \,ms^{-2}$) (in $\,ms^{-2}$)

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