An object thrown at a certain angle to the gr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The work done by a force is given by the formula $W = F \cdot s \cdot \cos(	heta)$, where $F$ is the force, $s$ is the displacement, and $	heta$

Vedclass · Accepted Answer

$0 \ J$

Vedclass · Answer

(A) The work done by a force is given by the formula $W = F \cdot s \cdot \cos(	heta)$, where $F$ is the force, $s$ is the displacement, and $	heta$ is the angle between the force and displacement vectors.In this case, the force of gravity acts vertically downwards $(F = mg)$.The displacement $s$ is the straight-line distance between the initial and final points.Since the initial and final points lie on the same horizontal line, the vertical displacement is $0$.Because the gravitational force acts only in the vertical direction, the work done by gravity is $W = F 	imes (	ext{vertical displacement}) = mg 	imes 0 = 0 \ J$.

An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

Similar Questions

Does the transfer of energy take place when you push a huge rock with all your might and fail to move it? Where is the energy you spend going?

Define average power.

Write an expression for the kinetic energy of an object.

The potential energy of a freely falling object decreases progressively. Does this violate the law of conservation of energy? Why?

Find the energy in $kWh$ consumed in $10$ hours by four devices of power $500\, W$ each. (in $kWh$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module