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(B) Given:Initial velocity $\vec{v_1} = +10 \, m/s$ (taking the direction of motion as positive).Final velocity $\vec{v_2} = -2 \, m/s$ (since it is i

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$-3$

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(B) Given:Initial velocity $\vec{v_1} = +10 \, m/s$ (taking the direction of motion as positive).Final velocity $\vec{v_2} = -2 \, m/s$ (since it is in the opposite direction).Time interval $t = 4 \, s$.Acceleration $\vec{a}$ is defined as the rate of change of velocity:$\vec{a} = \frac{\vec{v_2} - \vec{v_1}}{t}$Substituting the values:$\vec{a} = \frac{-2 - 10}{4} = \frac{-12}{4} = -3 \, m/s^2$.Thus,the acceleration produced is $-3 \, m/s^2$.

An object with a mass $10 \, kg$ moves at a constant velocity of $10 \, m/s$. $A$ constant force then acts for $4 \, s$ on the object and gives it a speed of $2 \, m/s$ in the opposite direction. The acceleration produced in it is ........ $m/s^2$.

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