An oil drum can be filled with oil in 40 min | vedclass

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Question

(A) Efficiency of filling pipe $= \frac{1}{40}$ drum/min.Efficiency of outlet pipe $= -\frac{1}{60}$ drum/min.Initial state of the drum $= \frac{2}{3}

Vedclass · Accepted Answer

$23 \frac{1}{3} 	ext{ min}$

Vedclass · Answer

(A) Efficiency of filling pipe $= \frac{1}{40}$ drum/min.Efficiency of outlet pipe $= -\frac{1}{60}$ drum/min.Initial state of the drum $= \frac{2}{3}$ full.Outlet pipe is opened for $15$ min,so the amount emptied $= 15 	imes \frac{1}{60} = \frac{1}{4}$ part.Remaining amount in the drum $= \frac{2}{3} - \frac{1}{4} = \frac{8-3}{12} = \frac{5}{12}$ part.Amount to be filled to make the drum full $= 1 - \frac{5}{12} = \frac{7}{12}$ part.Time required for the filling pipe to fill the remaining $\frac{7}{12}$ part $= \frac{7/12}{1/40} = \frac{7}{12} 	imes 40 = \frac{7 	imes 10}{3} = \frac{70}{3} = 23 \frac{1}{3} 	ext{ min}$.

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