An orange solid (X) on heating gives a colour | vedclass

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(A) The thermal decomposition of ammonium dichromate is given by: $(NH_4)_2Cr_2O_7 \rightarrow N_2(g) + Cr_2O_3(s) + 4H_2O(g)$.Here,$(X)$ is $(NH_4)_2

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$Mg_3N_2$

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(A) The thermal decomposition of ammonium dichromate is given by: $(NH_4)_2Cr_2O_7 \rightarrow N_2(g) + Cr_2O_3(s) + 4H_2O(g)$.Here,$(X)$ is $(NH_4)_2Cr_2O_7$ (orange solid),$(Y)$ is $N_2$ (colourless gas),and $(Z)$ is $Cr_2O_3$ (green residue).When the gas $(Y)$,which is $N_2$,reacts with magnesium metal,it forms magnesium nitride:$3Mg + N_2 \rightarrow Mg_3N_2$.$Mg_3N_2$ is a white solid substance.

An orange solid $(X)$ on heating gives a colourless gas $(Y)$ and only a green residue $(Z)$. Gas $(Y)$ on treatment with $Mg$ produces a white solid substance. Identify the white solid substance.

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