An organ pipe with both ends open has a length $L=25 \,cm$. An extra hole is created at position $\frac{L}{2}$. The lowest frequency of sound produced is (assume, speed of sound $=340 \,m/s$) (in $\,Hz$)

The end correction of a resonance column is $1 \, cm$. If the shortest length resonating with the tuning fork is $10 \, cm$,the next resonating length should be ..... $cm$.

While measuring the speed of sound by performing a resonance column experiment,a student gets the first resonance condition at a column length of $18\,cm$ during winter. Repeating the same experiment during summer,she measures the column length to be $x\,cm$ for the second resonance. Then

For sound waves, if the number of nodes for the $5^{th}$ harmonic of an open-ended pipe is $n$ and that for the $9^{th}$ harmonic of the same pipe with one of its ends closed is $m$, the ratio $\frac{n}{m}$ is :

$A$ closed organ pipe of length $L_c$ and an open organ pipe of length $L_o$ contain different gases of densities $\rho_1$ and $\rho_2$ respectively. The compressibility of the gases is the same in both the pipes. The gases are vibrating in their first overtone with the same frequency. What is the length of the open organ pipe?

$A$ pipe open at both ends of length $1.5 \,m$ is dipped in water such that the second overtone of the vibrating air column resonates with a tuning fork of frequency $330 \,Hz$. If the speed of sound in air is $330 \,m/s$, then the length of the pipe immersed in water is (Neglect end correction). (in $\,m$)