An organic compound 'X' showing the following | vedclass

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(C) The solubility profile of the compound '$X$' is as follows:$1$. Insoluble in water: Indicates it is likely a non-polar or high molecular weight or

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Benzamide

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(C) The solubility profile of the compound '$X$' is as follows:$1$. Insoluble in water: Indicates it is likely a non-polar or high molecular weight organic compound.$2$. Insoluble in $5\% \,HCl$: Indicates it is not a basic compound (like an amine).$3$. Insoluble in $10\% \,NaOH$: Indicates it is not an acidic compound (like a carboxylic acid or a phenol).$4$. Insoluble in $10\% \,NaHCO_3$: Confirms it is not a strong acid (like a carboxylic acid).Evaluating the options:- Oleic acid is a carboxylic acid,so it is soluble in $NaOH$ and $NaHCO_3$.- $o-$Toluidine is an amine,so it is soluble in $HCl$.- $m-$Cresol is a phenol,so it is soluble in $NaOH$.- Benzamide $(C_6H_5CONH_2)$ is a neutral compound. It is insoluble in water,$HCl$,$NaOH$,and $NaHCO_3$. Therefore,it matches the given solubility profile.

An organic compound '$X$' showing the following solubility profile is:
'$X$' $\xrightarrow{\text{water}}$ Insoluble
'$X$' $\xrightarrow{5\% \,HCl}$ Insoluble
'$X$' $\xrightarrow{10\% \,NaOH}$ Insoluble
'$X$' $\xrightarrow{10\% \,NaHCO_3}$ Insoluble

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An organic compound '$X$' showing the following solubility profile is:'$X$' $\xrightarrow{\text{water}}$ Insoluble'$X$' $\xrightarrow{5\% \,HCl}$ Insoluble'$X$' $\xrightarrow{10\% \,NaOH}$ Insoluble'$X$' $\xrightarrow{10\% \,NaHCO_3}$ Insoluble