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(A) The process described is the Lassaigne's test modification or a standard qualitative analysis for phosphorus. $1$. The organic compound is fused w

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Phosphorus

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(A) The process described is the Lassaigne's test modification or a standard qualitative analysis for phosphorus. $1$. The organic compound is fused with sodium peroxide $(Na_2O_2)$ to convert phosphorus into phosphate $(PO_4^{3-})$. $2$. Boiling with $HNO_3$ removes excess peroxide and ensures the phosphorus is in the phosphate form. $3$. Upon adding ammonium molybdate $(NH_4)_2MoO_4$ in the presence of $HNO_3$,a canary yellow precipitate of ammonium phosphomolybdate $(NH_4)_3PO_4 \cdot 12MoO_3$ is formed. $4$. Therefore,the element present is phosphorus.

An organic compound $A$ is oxidized with $Na_2O_2$ followed by boiling with $HNO_3$. The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate. Based on the above observation,the element present in the given compound is:

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