An organic compound CH_3-CH=CH-CH_2-CHO is ta | vedclass

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(D) Step $1$: Reaction in container $A$ with $H_2 / Ni$. $H_2 / Ni$ is a strong reducing agent that reduces both the alkene double bond and the aldehy

Vedclass · Accepted Answer

$P = CH_3(CH_2)_3CH_2OH$ and $Q = CH_3-CH=CH-CH_2-CH_2OH$

Vedclass · Answer

(D) Step $1$: Reaction in container $A$ with $H_2 / Ni$. $H_2 / Ni$ is a strong reducing agent that reduces both the alkene double bond and the aldehyde group. Thus, $CH_3-CH=CH-CH_2-CHO + 2H_2 \xrightarrow{Ni} CH_3-CH_2-CH_2-CH_2-CH_2OH$ (or $CH_3(CH_2)_3CH_2OH$). So, $P = CH_3(CH_2)_3CH_2OH$.Step $2$: Reaction in container $B$ with $LiAlH_4$. $LiAlH_4$ is a selective reducing agent that reduces the aldehyde group to a primary alcohol but does not reduce the isolated alkene double bond. Thus, $CH_3-CH=CH-CH_2-CHO \xrightarrow{LiAlH_4 / H_3O^+} CH_3-CH=CH-CH_2-CH_2OH$. So, $Q = CH_3-CH=CH-CH_2-CH_2OH$.Step $3$: Comparing with options, $P = CH_3(CH_2)_3CH_2OH$ and $Q = CH_3-CH=CH-CH_2-CH_2OH$ matches option $D$.

An organic compound $CH_3-CH=CH-CH_2-CHO$ is taken in two different containers $A$ and $B$. Sample in $A$ is treated with $H_2 / Ni$ forming new compound $P$. Sample in $B$ is treated with $LiAlH_4$ and hydrolyzed further forming new compound $Q$. Identify $P$ and $Q$.

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