An organic compound containing $C$,$H$,and $N$ gave the following analysis: $C = 40\%$,$H = 13.33\%$,and $N = 46.67\%$. Its empirical formula would be:
- A$C_2H_7N_2$
- B$CH_5N$
- C$CH_4N$
- D$C_2H_7N$
Explore More
Similar Questions
In an organic compound,the percentage of $C$ is $92.3 \%$. What is its empirical formula?
Easy
View SolutionAn organic compound gave the following results: $C = 53.3\%$,$H = 15.6\%$,$N = 31.1\%$. The molecular weight of the compound is $45$. What is the molecular formula of the compound?
Medium
View SolutionDetermine the empirical formula of an oxide of iron which has $69.9 \%$ iron and $30.1 \%$ dioxygen by mass.
Medium
View SolutionAt $STP$,$2.8 \, L$ of a gaseous substance weighs $5.5 \, g$. If the compound contains $N$ and $O$ atoms,its molecular formula will be ..............
Medium
View Solution$0.0833 \, mol$ of a carbohydrate with the empirical formula $CH_2O$ contains $1 \, g$ of hydrogen. What is the molecular formula of the carbohydrate?
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo