An organic compound contains carbon,hydrogen, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Calculate the percentage of oxygen: $\% O = 100 - (38.71 + 9.67) = 51.62 \%$. $2$. Calculate the relative number of moles for each element: $

Vedclass · Accepted Answer

$CH_3O$

Vedclass · Answer

(C) $1$. Calculate the percentage of oxygen: $\% O = 100 - (38.71 + 9.67) = 51.62 \%$. $2$. Calculate the relative number of moles for each element: $C = \frac{38.71}{12} = 3.226$ $H = \frac{9.67}{1} = 9.67$ $O = \frac{51.62}{16} = 3.226$ $3$. Determine the simplest molar ratio by dividing by the smallest value $(3.226)$: $C = \frac{3.226}{3.226} = 1$ $H = \frac{9.67}{3.226} \approx 3$ $O = \frac{3.226}{3.226} = 1$ $4$. The empirical formula is $CH_3O$.

An organic compound contains carbon,hydrogen,and oxygen. Its elemental analysis gives $38.71 \%$ of $C$ and $9.67 \%$ of $H$. The empirical formula of the compound would be $:-$

Similar Questions

Determine the empirical formula of an oxide of iron which has $69.9 \%$ iron and $30.1 \%$ dioxygen by mass.

Empirical formula of a compound is $CH_2O$ and its vapour density is $30$. The molecular formula of the compound is:

Caffeine has a molecular weight of $194$. If it contains $28.9\%$ by mass of nitrogen,the number of atoms of nitrogen in one molecule of caffeine is:

The weight percentage of $C$ and $H$ in a hydrocarbon is in the ratio of $4: 1$. What is its empirical formula?

An organic compound contains $C = 40\%$,$H = 13.33\%$,and $N = 46.67\%$. Its empirical formula is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module