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(A) The mass ratio of $C : H$ is $6 : 1$ and the mass ratio of $C : O$ is $3 : 4$. To compare them,we express $C : O$ in terms of the same $C$ mass $(

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$HCHO$

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(A) The mass ratio of $C : H$ is $6 : 1$ and the mass ratio of $C : O$ is $3 : 4$. To compare them,we express $C : O$ in terms of the same $C$ mass $(6)$: $C : O = 6 : 8$.Thus,the mass ratio $C : H : O = 6 : 1 : 8$.The atomic masses are $C = 12 \ g/mol$,$H = 1 \ g/mol$,and $O = 16 \ g/mol$.The number of moles for each element is:Moles of $C = \frac{6}{12} = 0.5 \ mol$Moles of $H = \frac{1}{1} = 1 \ mol$Moles of $O = \frac{8}{16} = 0.5 \ mol$The mole ratio $C : H : O = 0.5 : 1 : 0.5 = 1 : 2 : 1$.The empirical formula is $CH_2O$,which corresponds to $HCHO$ (formaldehyde).

An organic compound has the percentage of $C$ and $H$ in the ratio $6 : 1$ and the percentage of $C$ and $O$ in the ratio $3 : 4$. The compound is:

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