An organic compound has a triple bond and no double bond. It can be tested by:

$CH_3-C \equiv C-CH_3 \, \xrightarrow[{(2) Br_2}]{{(1) H_2 /Pd/CaCO_3}} \, (X) \, , \, (X)$ is

Propyne on cyclic polymerisation gives

Assertion : Acetylene on reacting with sodamide gives sodium acetylide and ammonia.
Reason : $sp$ hybridised carbon atoms of acetylene are considerably electronegative.

To synthesize the unsymmetrical alkyne $CH_3-C\equiv C-CH_2-CH_3$,the reagents needed would be:

Give chemical reactions for the following conversions:
$1$. $2-$bromobutane from $2-$butyne
$2$. $2-$propanol and $1-$propanol from propyne