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Question

(A) The reaction involves the alkaline hydrolysis (saponification) of an ester followed by acidification.$C_6H_5COOC_2H_5 + KOH 	ext{ (alc)} 	o C_6H

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Ethyl benzoate

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(A) The reaction involves the alkaline hydrolysis (saponification) of an ester followed by acidification.$C_6H_5COOC_2H_5 + KOH 	ext{ (alc)} 	o C_6H_5COOK + C_2H_5OH$Upon adding $HCl$,the potassium salt of the acid is converted into the corresponding carboxylic acid:$C_6H_5COOK + HCl 	o C_6H_5COOH (	ext{white solid}) + KCl$Since $C_6H_5COOH$ (benzoic acid) is a white solid that precipitates upon acidification,the starting compound is ethyl benzoate.

An organic compound is boiled with alcoholic potash. The product is cooled and acidified with $HCl$. $A$ white solid separates out. The starting compound may be

Similar Questions

The major product formed in the following reaction is:

The compound $(X)$ in the given reaction is:
$MeO-C_6H_4-CHO + (X) \xrightarrow{CH_3COONa, H_3O^+} MeO-C_6H_4-CH=CHCOOH$

In the following reaction,$X$ and $Y$ respectively are:
$C_2H_5OH$ $\xrightarrow{KMnO_4 / H^+} X$ $\xrightarrow{C_2H_5OH / H_2SO_4, \Delta} CH_3COOC_2H_5$

The major product $P$ formed in the following sequence of reactions is

In a set of reactions,ethylbenzene yielded a product $D$.
Ethylbenzene $\xrightarrow[KOH]{KMnO_4} B$ $\xrightarrow[FeCl_3]{Br_2} C$ $\xrightarrow[H^{+}]{C_2H_5OH} D$
$D$ would be

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