An organic compound with $C = 40\%$ and $H = 6.7\%$ will have the empirical formula

  • A
    $CH_2$
  • B
    $CH_2O$
  • C
    $C_3H_6O_3$
  • D
    $C_2H_4O_2$

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$A$ compound has the following composition by weight: $Na = 18.60 \%$,$S = 25.80 \%$,$H = 4.02 \%$,and $O = 51.58 \%$. Assuming that all the hydrogen atoms in the compound are part of water of crystallisation,the correct molecular formula of the compound is:

An organic compound contains $49.3\%$ carbon,$6.84\%$ hydrogen and its vapour density is $73$. The molecular formula of the compound is:

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Complete combustion of $750 \ g$ of an organic compound provides $420 \ g$ of $CO_2$ and $210 \ g$ of $H_2O$. The percentage composition of carbon and hydrogen in the organic compound is $15.3$ and ............. respectively. (Round off to the Nearest Integer)

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