An organic compound with the molecular formul | vedclass

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(B) $1$. The molecular formula $C_9H_{10}O$ and the formation of a $2,4-DNP$ derivative indicate the presence of a carbonyl group (aldehyde or ketone)

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(B) $1$. The molecular formula $C_9H_{10}O$ and the formation of a $2,4-DNP$ derivative indicate the presence of a carbonyl group (aldehyde or ketone).$2$. The compound reduces Tollen's reagent,which confirms it is an aldehyde.$3$. It undergoes the Cannizzaro reaction,which implies it does not have any $\alpha-$hydrogen atoms.$4$. On vigorous oxidation,it yields $1,2-$benzenedicarboxylic acid (phthalic acid),which indicates that the compound is an ortho-substituted benzene derivative.$5$. Combining these facts,the compound must be $2-$ethylbenzaldehyde. The ethyl group at the ortho position prevents $\alpha-$hydrogens from being available at the carbon attached to the benzene ring,allowing for the Cannizzaro reaction.$6$. Thus,the structure is $2-$ethylbenzaldehyde.

An organic compound with the molecular formula $C_9H_{10}O$ forms a $2,4-DNP$ derivative,reduces Tollen's reagent and undergoes Cannizzaro reaction; on vigorous oxidation it gives $1,2-$benzenedicarboxylic acid. The structure of the organic compound is:

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