An unknown compound $(A)$ has a molecular formula $C_4H_6$. When $(A)$ is treated with excess of $Br_2$, a new substance $(B)$ with formula $C_4H_6Br_4$ is formed. $(A)$ forms a white precipitate with ammoniacal silver nitrate solution. $(A)$ may be:

  • A
    but-$1$-yne
  • B
    but-$2$-yne
  • C
    but-$1$-ene
  • D
    but-$2$-ene

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Similar Questions

$A$ hydrocarbon with molecular formula $C_6H_6$ decolourises $Br_2$ water and gives a precipitate with ammoniacal $AgNO_3$. The hydrocarbon is:

$Ca + C$ $\xrightarrow[\Delta ]{} A$ $\xrightarrow{H_2O} B$ $\xrightarrow{\text{cyclic polymerisation}} C$
Product $B$ and $C$ are respectively

Acetylene reacts with ammoniacal $AgNO_{3}$ to form:

Consider the following reaction sequences and choose the correct option:
$L \xrightarrow{Na/liq. NH_3} Ph-C \equiv C-Me \xrightarrow[Lindlar's \ Catalyst]{H_2, Pd/C} K$
$L \xrightarrow{HBr, \text{benzoyl peroxide}} N$
$K \xrightarrow{HBr} M$

What happens when a mixture of acetylene and hydrogen is passed over heated Lindlar's catalyst?

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