An unsaturated hydrocarbon X absorbs two hydr | vedclass

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(A) $1$. The hydrocarbon $X$ absorbs two hydrogen molecules,which indicates it has two degrees of unsaturation (either two double bonds,one triple bon

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(A) $1$. The hydrocarbon $X$ absorbs two hydrogen molecules,which indicates it has two degrees of unsaturation (either two double bonds,one triple bond,or one ring and one double bond). $2$. Ozonolysis $(O_3/Zn/H_2O)$ of $X$ gives product $A$,which upon oxidation with Tollens' reagent $([Ag(NH_3)_2]^{+})$ yields $3$-oxo-hexane dicarboxylic acid $(B)$. $3$. The structure of $3$-oxo-hexane dicarboxylic acid is $HOOC-CH_2-C(=O)-CH_2-CH_2-COOH$. $4$. This indicates that $A$ must be the corresponding dialdehyde: $OHC-CH_2-C(=O)-CH_2-CH_2-CHO$. $5$. Working backwards from the ozonolysis product,the structure of $X$ is $3$-methylenecyclohexene,which has a double bond in the ring and an exocyclic double bond. $6$. Therefore,the correct structure for $X$ is the one shown in option $A$.

An unsaturated hydrocarbon $X$ absorbs two hydrogen molecules on catalytic hydrogenation,and also gives the following reaction: $X$ $\xrightarrow[Zn/H_2O]{O_3} A$ $\xrightarrow{[Ag(NH_3)_2]^{+}} B$ ($3$-oxo-hexane dicarboxylic acid). $X$ will be

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