The angular momentum of a single particle moving with constant speed along a circular path:

Two cars $A$ and $B$ each of mass $10^3 \text{ kg}$ are moving on parallel tracks separated by a distance of $10 \text{ m}$, in the same direction with speeds $72 \text{ km/h}$ and $36 \text{ km/h}$. The magnitude of angular momentum of car $A$ with respect to car $B$ is . . . . . . $\text{J} \cdot \text{s}$.

The position of a particle is given by $\vec r = (\hat i + 2\hat j - \hat k)$ and its momentum is $\vec p = (3\hat i + 4\hat j - 2\hat k)$. The angular momentum is perpendicular to:

In an orbital motion,the angular momentum vector is

$A$ small mass $m$ is attached to a massless string whose other end is fixed at $P$ as shown in the figure. The mass is undergoing circular motion in the $x-y$ plane with centre at $O$ and constant angular speed $\omega$. If the angular momentum of the system,calculated about $O$ and $P$ are denoted by $\vec{L}_O$ and $\vec{L}_P$ respectively,then

$A$ particle of mass $1 \ kg$ is moving with a linear velocity of $2 \ ms^{-1}$ parallel to the positive $X$-axis. During this motion,its minimum distance from the origin is $12 \ cm$. The angular momentum of this particle about the origin is ....... $Js$.