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(B) $1$. The reaction of aniline with $NaNO_{2}/HCl$ at $273-278 \ K$ results in the formation of benzenediazonium chloride $(X)$.$2$. Benzenediazoniu

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p-(Dimethylamino)azobenzene

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(B) $1$. The reaction of aniline with $NaNO_{2}/HCl$ at $273-278 \ K$ results in the formation of benzenediazonium chloride $(X)$.$2$. Benzenediazonium chloride $(X)$ then undergoes an electrophilic aromatic substitution reaction (coupling reaction) with $N,N-dimethylaniline$ in a weakly acidic medium.$3$. The coupling occurs at the para-position of $N,N-dimethylaniline$ to form $p-(dimethylamino)azobenzene$ $(Y)$,which is a yellow-orange coloured dye.$4$. The structure of $Y$ is $C_6H_5-N=N-C_6H_4-N(CH_3)_2$.

Aniline in a set of the following reactions yielded a coloured product $Y$.
Aniline $\xrightarrow[(273-278 \ K)]{NaNO_{2}/HCl} X$ $\xrightarrow{N,N-dimethylaniline} Y$
The structure of $Y$ would be

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Aniline in a set of the following reactions yielded a coloured product $Y$.Aniline $\xrightarrow[(273-278 \ K)]{NaNO_{2}/HCl} X$ $\xrightarrow{N,N-dimethylaniline} Y$The structure of $Y$ would be