Aniline reacts with acetaldehyde to form

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Question

(A) Aniline $(C_6H_5NH_2)$ reacts with acetaldehyde $(CH_3CHO)$ in the presence of a trace of acid to form a Schiff's base ($N$-ethylideneaniline,$C_6

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Schiff's base

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(A) Aniline $(C_6H_5NH_2)$ reacts with acetaldehyde $(CH_3CHO)$ in the presence of a trace of acid to form a Schiff's base ($N$-ethylideneaniline,$C_6H_5N=CHCH_3$) and water $(H_2O)$.The reaction is:$C_6H_5NH_2 + CH_3CHO \xrightarrow{	ext{trace of acid}} C_6H_5N=CHCH_3 + H_2O$This product is a type of imine,specifically known as a Schiff's base.

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