Aniline,when diazotized in cold and then trea | vedclass

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(A) Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2$ and $HCl$ at $0-5 \ ^{\circ}C$ to form benzenediazonium chloride $(C_6H_5N_2^+Cl^-)$.This diazonium sa

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$(CH_3)_2N-C_6H_4-N=N-C_6H_5$

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(A) Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2$ and $HCl$ at $0-5 \ ^{\circ}C$ to form benzenediazonium chloride $(C_6H_5N_2^+Cl^-)$.This diazonium salt then undergoes an electrophilic substitution (coupling reaction) with $N,N$-dimethylaniline at the para-position to form $p$-(dimethylamino)azobenzene,which is a coloured azo dye.The reaction is:$C_6H_5N_2^+Cl^- + C_6H_5N(CH_3)_2 \rightarrow (CH_3)_2N-C_6H_4-N=N-C_6H_5 + HCl$Thus,the correct structure is $(CH_3)_2N-C_6H_4-N=N-C_6H_5$.

Aniline,when diazotized in cold and then treated with $N,N$-dimethylaniline,gives a coloured product. Its structure would be:

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