The reaction of aqueous $NaOH$ with white $P_4$ is given by: $P_4 + NaOH (aq) \rightarrow PH_3 + X$. The compound $X$ is:
- A$NaH_2PO_2$
- B$NaHPO_4$
- C$Na_2CO_3$
- D$NaHCO_3$
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