Aqueous ammonia readily dissolves $AgCl$ because
- A$NH_3$ molecules readily solvate $Ag^{+}$ and $Cl^{-}$ ions
- B$NH_3$ molecules abstract chloride from $AgCl$ to form $NH_4Cl$
- Ca soluble complex $[Ag(NH_3)_6]^{+}$ is formed
- Da soluble complex $[Ag(NH_3)_2]^{+}$ is formed
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Similar Questions
Urea reacts with water to form $A$ which will decompose to form $B$. $B$ when passed through $Cu^{2+}_{(aq)}$,a deep blue coloured solution $C$ is formed. What is the formula of $C$ from the following?
MediumNEET 2020
View Solution$CO$ is a stronger ligand than $Cl^{-}$ because:
$Ag^{+} + NH_3 \rightleftharpoons [Ag(NH_3)]^{+}$; $k_1 = 3.5 \times 10^{-3}$
$[Ag(NH_3)]^{+} + NH_3 \rightleftharpoons [Ag(NH_3)_2]^{+}$; $k_2 = 1.7 \times 10^{-3}$
Then the formation constant of $[Ag(NH_3)_2]^{+}$ is
$[Ag(NH_3)]^{+} + NH_3 \rightleftharpoons [Ag(NH_3)_2]^{+}$; $k_2 = 1.7 \times 10^{-3}$
Then the formation constant of $[Ag(NH_3)_2]^{+}$ is
The $\pi-$acid ligand which uses its $d-$orbital during synergic bonding in its complex compound.
Medium
View SolutionWhich product is formed when an excess of $KCN$ is added to a solution of copper sulfate?
Medium
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