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(A) When halide ions like $Cl^{-}$,$Br^{-}$,and $I^{-}$ are treated with $AgNO_3$ solution,they form silver halides.$AgCl$ is a white precipitate that

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$Cl^{-}$

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(A) When halide ions like $Cl^{-}$,$Br^{-}$,and $I^{-}$ are treated with $AgNO_3$ solution,they form silver halides.$AgCl$ is a white precipitate that is soluble in $NH_4OH$ due to the formation of a soluble complex $[Ag(NH_3)_2]Cl$.$AgBr$ is a pale yellow precipitate that is sparingly soluble in $NH_4OH$.$AgI$ is a yellow precipitate that is insoluble in $NH_4OH$.Since the precipitate is white and dissolves in $NH_4OH$,the radical present is $Cl^{-}$.Chemical reaction:$AgNO_3 + NaCl ightarrow AgCl \downarrow (	ext{white}) + NaNO_3$$AgCl + 2NH_4OH ightarrow [Ag(NH_3)_2]Cl + 2H_2O$

An aqueous solution of a salt,when treated with $AgNO_3$ solution,gives a white precipitate which dissolves in $NH_4OH$. The radical present in the salt is:

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