Are the following pairs of statements negations of each other:
$1$. The number $x$ is a rational number.
$2$. The number $x$ is an irrational number.

Find the function $f(x_{1}, x_{2}, x_{3})$ that satisfies $f(x_{1}, x_{2}, x_{3}) = 1$ at $x_{1} = 1, x_{2} = 0, x_{3} = 0$.

$(p \wedge r) \Leftrightarrow (p \wedge (\sim q))$ is equivalent to $(\sim p)$ when $r$ is.

$p$: If $7$ is an odd number,then $7$ is divisible by $2$.
$q$: If $7$ is a prime number,then $7$ is an odd number.
If $V_1$ and $V_2$ are the respective truth values of the contrapositive of $p$ and $q$,then $(V_1, V_2) \equiv$

If the truth value of the statement $(P \wedge (\sim R)) \rightarrow ((\sim R) \wedge Q)$ is $F$,then the truth value of which of the following is $F$?

Which of the following is not a statement?