Area of a square $= (........... )^{2}.$

The ratio of the measures of the sides of a triangle is $3: 4: 6$. If the semiperimeter of the triangle is $39 \, cm$,the measure of the longest side of the triangle is ............ $cm$.

In $\Delta ABC$,$AB = 20 \, cm$,$BC = 48 \, cm$,and $AC = 52 \, cm$,find the area of $\Delta ABC$. (in $, cm^2$)

The sides of a triangle are $56 \ cm$,$60 \ cm$,and $52 \ cm$ long. Then the area of the triangle is (in $cm^2$)

Calculate the area of the shaded region in the figure.

In quadrilateral $ABCD$,$AB = 20 \, cm$,$BC = 15 \, cm$,$CD = 12 \, cm$,$DA = 17 \, cm$ and $\angle B = 90^{\circ}$. Find the area of the quadrilateral in $cm^2$.