Arrange NH_4^+,H_2O,H_3O^{+},HF,and OH^{-} in | vedclass

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Question

(C) The acidic strength depends on the ability to donate a proton $(H^+)$. Comparing the species: $OH^{-}$ is a strong base,so it is the least acidic.

Vedclass · Accepted Answer

$OH^{-} < H_2O < NH_4^+ < HF < H_3O^{+}$

Vedclass · Answer

(C) The acidic strength depends on the ability to donate a proton $(H^+)$. Comparing the species: $OH^{-}$ is a strong base,so it is the least acidic. $H_2O$ is amphoteric but acts as a very weak acid. $NH_4^+$ is a weak acid $(pK_a \approx 9.25)$. $HF$ is a stronger acid than $NH_4^+$ $(pK_a \approx 3.17)$. $H_3O^{+}$ is a strong acid in aqueous solution $(pK_a \approx -1.74)$. Therefore,the increasing order of acidic nature is: $OH^{-} < H_2O < NH_4^+ < HF < H_3O^{+}$.

Arrange $NH_4^+$,$H_2O$,$H_3O^{+}$,$HF$,and $OH^{-}$ in increasing order of acidic nature.

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