Arrange the following alkanes in order of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The boiling point of alkanes depends on the surface area of the molecule.As the branching in the alkane increases,the surface area decreases,which

Vedclass · Accepted Answer

$A > B > C$

Vedclass · Answer

(A) The boiling point of alkanes depends on the surface area of the molecule.As the branching in the alkane increases,the surface area decreases,which leads to weaker van der Waals forces of attraction.Pentane $(A)$ is a straight-chain alkane with the largest surface area.$2-$Methylbutane $(B)$ has one branch,reducing its surface area compared to pentane.$2,2-$Dimethylpropane $(C)$ is the most branched isomer,resulting in the smallest surface area and the lowest boiling point.Therefore,the order of boiling points is $A > B > C$.

Arrange the following alkanes in order of their boiling points:
$A$. Pentane
$B$. $2-$Methylbutane
$C$. $2,2-$Dimethylpropane

Similar Questions

Which of the following is true for the given reaction: $R - H + X_2 \xrightarrow{hv} R - X + H - X$?

Which of the following products is $NOT$ formed by the reaction between methane and chlorine in the presence of sunlight?

Which product is obtained on heating sodium acetate with sodalime?

Select the reaction$(s)$ that would result in the formation of $2-$bromopropane.
$(I) \ CH_3-CH=CH_2 + HBr \xrightarrow{\text{peroxide}}$
$(II) \ CH_3-CH=CH_2 + HBr \xrightarrow{CCl_4}$
$(III) \ CH_3-CH_2-CH_3 + Br_2 \xrightarrow{hv}$
$(IV) \ CH_3-CH=CH_2 + Br_2 \xrightarrow{CCl_4}$

Aluminium carbide on reacting with water gives

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following alkanes in order of their boiling points:$A$. Pentane$B$. $2-$Methylbutane$C$. $2,2-$Dimethylpropane