Arrange the following anions in decreasing or | vedclass

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(A) The stability of an anion is determined by the electronegativity of the atom carrying the negative charge. For elements in the same period $(C, N,

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$Cl^{\Theta} > OH^{\Theta} > NH_2^{\Theta} > CH_3^{\Theta}$

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(A) The stability of an anion is determined by the electronegativity of the atom carrying the negative charge. For elements in the same period $(C, N, O)$,stability increases as electronegativity increases: $CH_3^{\Theta} When comparing elements in the same group,the size of the atom is the dominant factor. $Cl^{\Theta}$ is much larger than $O^{\Theta}$,$N^{\Theta}$,or $C^{\Theta}$,which allows the negative charge to be dispersed over a larger volume,making $Cl^{\Theta}$ the most stable anion among the given species. Therefore,the decreasing order of stability is $Cl^{\Theta} > OH^{\Theta} > NH_2^{\Theta} > CH_3^{\Theta}$.

Arrange the following anions in decreasing order of their stability:
$CH_3^{\Theta}, NH_2^{\Theta}, OH^{\Theta}, Cl^{\Theta}$

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Arrange the following anions in decreasing order of their stability:$CH_3^{\Theta}, NH_2^{\Theta}, OH^{\Theta}, Cl^{\Theta}$