Arrange the following compounds in the decreasing order of their reactivity towards $HBr$:
$(a)$ $(CH_3)_2C=CH_2$
$(b)$ $CH_3O-C(CH_3)=CH_2$
$(c)$ $CH_3OCH_2-C(CH_3)=CH_2$

  • A
    $a > b > c$
  • B
    $b > a > c$
  • C
    $b > c > a$
  • D
    $a > c > b$

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