Arrange the aqueous solutions of the followin | vedclass

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(B) $CuSO_4$ $(I)$ is a salt of a strong acid $(H_2SO_4)$ and a weak base $(Cu(OH)_2)$,so its aqueous solution is acidic $(pH < 7)$.$KCl$ $(III)$ is a

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$I < III < II$

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(B) $CuSO_4$ $(I)$ is a salt of a strong acid $(H_2SO_4)$ and a weak base $(Cu(OH)_2)$,so its aqueous solution is acidic $(pH $KCl$ $(III)$ is a salt of a strong acid $(HCl)$ and a strong base $(KOH)$,so its aqueous solution is neutral $(pH = 7)$.$NaCN$ $(II)$ is a salt of a weak acid $(HCN)$ and a strong base $(NaOH)$,so its aqueous solution is basic $(pH > 7)$.Therefore,the increasing order of $pH$ is $I < III < II$.

Arrange the aqueous solutions of the following salts in the increasing order of $pH$: $CuSO_4$ $(I)$,$NaCN$ $(II)$,$KCl$ $(III)$.

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