Arrange the bonds in order of increasing ioni | vedclass

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(B) The ionic character in a molecule is dependent upon the electronegativity difference between the constituting atoms. The greater the difference,th

Vedclass · Accepted Answer

$N_{2} < ClF_{3} < SO_{2} < K_{2}O < LiF$

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(B) The ionic character in a molecule is dependent upon the electronegativity difference between the constituting atoms. The greater the difference,the greater will be the ionic character of the molecule.$1$. $N_{2}$: Electronegativity difference is $0$ (non-polar covalent).$2$. $SO_{2}$: Electronegativity difference between $S$ $(2.58)$ and $O$ $(3.44)$ is $0.86$.$3$. $ClF_{3}$: Electronegativity difference between $Cl$ $(3.16)$ and $F$ $(3.98)$ is $0.82$.$4$. $K_{2}O$: Electronegativity difference between $K$ $(0.82)$ and $O$ $(3.44)$ is $2.62$.$5$. $LiF$: Electronegativity difference between $Li$ $(0.98)$ and $F$ $(3.98)$ is $3.00$.Comparing these values,the order of increasing ionic character is $N_{2} < ClF_{3} < SO_{2} < K_{2}O < LiF$.

Arrange the bonds in order of increasing ionic character in the molecules: $LiF$,$K_{2}O$,$N_{2}$,$SO_{2}$ and $ClF_{3}$

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