Arrange the following carbocations in the inc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The stability of carbocations increases with the number of electron-donating alkyl groups due to the $+I$ effect and hyperconjugation. The order o

Vedclass · Accepted Answer

$2 < 4 < 1 < 3$

Vedclass · Answer

(A) The stability of carbocations increases with the number of electron-donating alkyl groups due to the $+I$ effect and hyperconjugation. The order of stability is $3^\circ > 2^\circ > 1^\circ > ext{methyl}$.$3$: $(CH_3)_3C^+$ ($3^\circ$ carbocation)$1$: $CH_3-CH^+-CH_3$ ($2^\circ$ carbocation)$4$: $CH_3-CH_2^+$ ($1^\circ$ carbocation)$2$: $CH_3^+$ (Methyl carbocation)Thus,the increasing order of stability is $2 < 4 < 1 < 3$.

Arrange the following carbocations in the increasing order of stability with respect to their labels:
Label Carbocation
$1$ $CH_3-CH^+-CH_3$
$2$ $CH_3^+$
$3$ $(CH_3)_3C^+$
$4$ $CH_3-CH_2^+$

Similar Questions

The shape of a carbonium ion (carbocation) is:

The correct order of stability of the given carbocations is:

What is the increasing order of stability for the carbanions $P: \bar{C}H_3$,$Q: C_6H_5\bar{C}H_2$,$R: (CH_3)_2\bar{C}H$,and $S: H_2\bar{C}^{-}CH=CH_2$?

Which of the following is the most stable among the given ions?

What are free radicals,carbanions,and carbocations? How are they formed?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Label	Carbocation
$1$	$CH_3-CH^+-CH_3$
$2$	$CH_3^+$
$3$	$(CH_3)_3C^+$
$4$	$CH_3-CH_2^+$

Arrange the following carbocations in the increasing order of stability with respect to their labels: LabelCarbocation$1$$CH_3-CH^+-CH_3$$2$$CH_3^+$$3$$(CH_3)_3C^+$$4$$CH_3-CH_2^+$