Arrange the following Cobalt complexes in the | vedclass

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(B) The $CFSE$ value depends on two main factors:$1$. Oxidation state of the central metal ion: Higher oxidation state leads to higher $CFSE$.$2$. Str

Vedclass · Accepted Answer

$B < A < C < D$

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(B) The $CFSE$ value depends on two main factors:$1$. Oxidation state of the central metal ion: Higher oxidation state leads to higher $CFSE$.$2$. Strength of the ligand (Spectrochemical series): Stronger ligands cause larger splitting.Let's analyze the complexes:- $[Co(H_{2}O)_{6}]^{2+}$: $Co^{2+}$ $(d^{7})$,weak field ligand $(H_{2}O)$.- $[CoF_{6}]^{3-}$: $Co^{3+}$ $(d^{6})$,weak field ligand $(F^{-})$.- $[Co(NH_{3})_{6}]^{3+}$: $Co^{3+}$ $(d^{6})$,strong field ligand $(NH_{3})$.- $[Co(en)_{3}]^{3+}$: $Co^{3+}$ $(d^{6})$,very strong field ligand $(en)$.Comparing $B$ $(Co^{2+})$ and $A$ $(Co^{3+})$,$B$ has a lower oxidation state,so it has lower $CFSE$. Among the $Co^{3+}$ complexes,the order of ligand strength is $F^{-} Thus,the increasing order of $CFSE$ is: $[Co(H_{2}O)_{6}]^{2+} < [CoF_{6}]^{3-} < [Co(NH_{3})_{6}]^{3+} < [Co(en)_{3}]^{3+}$,which corresponds to $B < A < C < D$.

Similar Questions

In which of the following complexes of the $Co$ (at. no. $27$),will the magnitude of $\Delta_o$ be the highest?

Arrange the following ligands in the order of increasing field strength:
$H_2O$ $(I)$,$CO$ $(II)$,$NH_3$ $(III)$,$I^{-}$ $(IV)$,$F^{-}$ $(V)$

Which of the following order of $CFSE$ is incorrect?

Which of the following complexes will have the lowest value of $\Delta_0$?

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