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(A) The conductivity of a coordination complex in an aqueous solution depends on the number of ions it produces upon dissociation. More ions lead to h

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$[Co(NH_{3})_{3}Cl_{3}] < [Co(NH_{3})_{4}Cl_{2}]Cl < [Cr(NH_{3})_{5}Cl]Cl_{2} < [Co(NH_{3})_{6}]Cl_{3}$

Vedclass · Answer

(A) The conductivity of a coordination complex in an aqueous solution depends on the number of ions it produces upon dissociation. More ions lead to higher conductivity.						$Compound$			$Number \ of \ ions$							$[Co(NH_{3})_{3}Cl_{3}]$			$0$							$[Co(NH_{3})_{4}Cl_{2}]Cl$			$2$							$[Cr(NH_{3})_{5}Cl]Cl_{2}$			$3$							$[Co(NH_{3})_{6}]Cl_{3}$			$4$			Thus,the increasing order of conductivity is: $[Co(NH_{3})_{3}Cl_{3}] < [Co(NH_{3})_{4}Cl_{2}]Cl < [Cr(NH_{3})_{5}Cl]Cl_{2} < [Co(NH_{3})_{6}]Cl_{3}$.

Arrange the following complexes in the increasing order of conductivity of their solution:
$[Co(NH_{3})_{3}Cl_{3}], [Co(NH_{3})_{4}Cl_{2}]Cl, [Co(NH_{3})_{6}]Cl_{3}, [Cr(NH_{3})_{5}Cl]Cl_{2}$

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$(IV) Mg[Cr(NH_3)(NO_2)_5]$

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Arrange the following complexes in the increasing order of conductivity of their solution:$[Co(NH_{3})_{3}Cl_{3}], [Co(NH_{3})_{4}Cl_{2}]Cl, [Co(NH_{3})_{6}]Cl_{3}, [Cr(NH_{3})_{5}Cl]Cl_{2}$