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(B) The reactivity of carbonyl compounds towards nucleophilic addition reaction $(NAR)$ depends on two factors: steric hindrance and electronic effect

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$III > II > I$

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(B) The reactivity of carbonyl compounds towards nucleophilic addition reaction $(NAR)$ depends on two factors: steric hindrance and electronic effects.$1$. Steric hindrance: Smaller groups around the carbonyl carbon allow easier attack by the nucleophile.$2$. Electronic effects: Electron-donating groups (like alkyl groups) decrease the electrophilicity of the carbonyl carbon,while electron-withdrawing groups increase it.Comparing the given compounds:$(III)$ $CH_3CHO$ (Acetaldehyde) has one methyl group and one hydrogen atom.$(II)$ $CH_3COCH_3$ (Acetone) has two methyl groups,which provide more steric hindrance and electron-donating effect than acetaldehyde.$(I)$ $C_6H_5COCH_3$ (Acetophenone) has a phenyl group,which provides significant steric hindrance and also resonance stabilization,making the carbonyl carbon less electrophilic.Thus,the order of reactivity is $CH_3CHO > CH_3COCH_3 > C_6H_5COCH_3$,which corresponds to $(III) > (II) > (I)$.

List-$I$ Reaction	List-$II$ Reagents
$A$. Hoffmann Degradation	$I$. Conc. $KOH, \Delta$
$B$. Clemmensen reduction	$II$. $CHCl_3, NaOH / H_3O^{+}$
$C$. Cannizzaro reaction	$III$. $Br_2, NaOH$
$D$. Reimer-Tiemann reaction	$IV$. $Zn-Hg / HCl$

Arrange the following compounds in decreasing order of reactivity towards nucleophilic addition reaction:
$(I)$ $C_6H_5COCH_3$
$(II)$ $CH_3COCH_3$
$(III)$ $CH_3CHO$

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Match List-$I$ with List-$II$.

List-$I$ Reaction List-$II$ Reagents

$A$. Hoffmann Degradation $I$. Conc. $KOH, \Delta$

$B$. Clemmensen reduction $II$. $CHCl_3, NaOH / H_3O^{+}$

$C$. Cannizzaro reaction $III$. $Br_2, NaOH$

$D$. Reimer-Tiemann reaction $IV$. $Zn-Hg / HCl$

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Arrange the following compounds in decreasing order of reactivity towards nucleophilic addition reaction:$(I)$ $C_6H_5COCH_3$$(II)$ $CH_3COCH_3$$(III)$ $CH_3CHO$