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(A) The molecular masses of the given compounds are in the range $44$ to $46 \ g/mol$.$CH_3CH_2OH$ (ethanol) exhibits extensive intermolecular $H$-bon

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$CH_3CH_2CH_3 < CH_3OCH_3 < CH_3CHO < CH_3CH_2OH$

Vedclass · Answer

(A) The molecular masses of the given compounds are in the range $44$ to $46 \ g/mol$.$CH_3CH_2OH$ (ethanol) exhibits extensive intermolecular $H$-bonding,leading to molecular association,which results in the highest boiling point.$CH_3CHO$ (acetaldehyde) is more polar than $CH_3OCH_3$ (methoxy methane),resulting in stronger dipole-dipole interactions.$CH_3CH_2CH_3$ (propane) is a non-polar alkane with only weak van der Waals forces.Therefore,the increasing order of boiling points is: $CH_3CH_2CH_3 < CH_3OCH_3 < CH_3CHO < CH_3CH_2OH$.

Arrange the following compounds in increasing order of their boiling points:
$CH_3CHO, CH_3CH_2OH, CH_3OCH_3, CH_3CH_2CH_3$

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Arrange the following compounds in increasing order of their boiling points:$CH_3CHO, CH_3CH_2OH, CH_3OCH_3, CH_3CH_2CH_3$