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(A) The boiling point depends on the intermolecular forces present in the compounds.$1$. $CH_3CH_2CH_2CH_2OH$ (butan-$1$-ol) has intermolecular hydrog

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$CH_3CH_2CH_2CH_3 < C_2H_5OC_2H_5 < CH_3CH_2CH_2CHO < CH_3CH_2CH_2CH_2OH$

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(A) The boiling point depends on the intermolecular forces present in the compounds.$1$. $CH_3CH_2CH_2CH_2OH$ (butan-$1$-ol) has intermolecular hydrogen bonding,resulting in the highest boiling point.$2$. $CH_3CH_2CH_2CHO$ (butanal) is a polar molecule with dipole-dipole interactions,which are stronger than the forces in ethers and alkanes.$3$. $C_2H_5OC_2H_5$ (ethoxyethane) has weak dipole-dipole interactions.$4$. $CH_3CH_2CH_2CH_3$ (butane) is a non-polar alkane with only weak van der Waals dispersion forces,resulting in the lowest boiling point.Thus,the increasing order of boiling points is: $CH_3CH_2CH_2CH_3 < C_2H_5OC_2H_5 < CH_3CH_2CH_2CHO < CH_3CH_2CH_2CH_2OH$.

Arrange the following compounds in the increasing order of their boiling points:
$CH_3CH_2CH_2CHO$,$CH_3CH_2CH_2CH_2OH$,$C_2H_5OC_2H_5$,$CH_3CH_2CH_2CH_3$

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Arrange the following compounds in the increasing order of their boiling points:$CH_3CH_2CH_2CHO$,$CH_3CH_2CH_2CH_2OH$,$C_2H_5OC_2H_5$,$CH_3CH_2CH_2CH_3$