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(B) The stability of alkyl free radicals is determined by the number of alkyl groups attached to the radical carbon,which provide stability through th

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$iv > iii > ii > i$

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(B) The stability of alkyl free radicals is determined by the number of alkyl groups attached to the radical carbon,which provide stability through the inductive effect and hyperconjugation.$3^{\circ}$ free radicals are the most stable,followed by $2^{\circ}$,$1^{\circ}$,and methyl radicals.Vinyl free radicals $(CH_2=\dot{C}H)$ are significantly less stable because the unpaired electron is in an $sp^2$ hybridized orbital,which has more $s$-character and is more electronegative.Thus,the stability order is: $(CH_3)_3\dot{C} (3^{\circ}) > CH_3-\dot{C}H-CH_3 (2^{\circ}) > \dot{C}H_3 (1^{\circ}) > CH_2=\dot{C}H$ (vinyl).The correct order is $iv > iii > ii > i$.

Arrange the following free radicals in the correct order of their stability:
$(i)$ $CH_2=\dot{C}H$
$(ii)$ $\dot{C}H_3$
$(iii)$ $CH_3-\dot{C}H-CH_3$
$(iv)$ $(CH_3)_3\dot{C}$

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Arrange the following free radicals in the correct order of their stability:$(i)$ $CH_2=\dot{C}H$$(ii)$ $\dot{C}H_3$$(iii)$ $CH_3-\dot{C}H-CH_3$$(iv)$ $(CH_3)_3\dot{C}$