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(A) The basic strength of amines depends on the electron-donating inductive effect $(+I)$ of alkyl groups and the resonance effect of the aryl group.$

Vedclass · Accepted Answer

$(C_2H_5)_2NH > C_2H_5NH_2 > NH_3 > C_6H_5NH_2$

Vedclass · Answer

(A) The basic strength of amines depends on the electron-donating inductive effect $(+I)$ of alkyl groups and the resonance effect of the aryl group.$1$. $(C_2H_5)_2NH$ (secondary amine) is the most basic due to the $+I$ effect of two ethyl groups.$2$. $C_2H_5NH_2$ (primary amine) is next,having one ethyl group.$3$. $NH_3$ is less basic than aliphatic amines.$4$. $C_6H_5NH_2$ (aniline) is the least basic because the lone pair on nitrogen is delocalized into the benzene ring via resonance.Therefore,the decreasing order is: $(C_2H_5)_2NH > C_2H_5NH_2 > NH_3 > C_6H_5NH_2$.

Arrange the following in decreasing order of their basic strength:
$C_6H_5NH_2, C_2H_5NH_2, (C_2H_5)_2NH, NH_3$

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Arrange the following in decreasing order of their basic strength:$C_6H_5NH_2, C_2H_5NH_2, (C_2H_5)_2NH, NH_3$