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(B) The acid strength is determined by the stability of the conjugate base. $1.$ In $(x) CH_3SO_3H$,the conjugate base $CH_3SO_3^-$ is highly stabiliz

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$x < y < z$

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(B) The acid strength is determined by the stability of the conjugate base. $1.$ In $(x) CH_3SO_3H$,the conjugate base $CH_3SO_3^-$ is highly stabilized by resonance over three oxygen atoms,making it the strongest acid among the three. $2.$ In $(y) CH_3COOH$,the conjugate base $CH_3COO^-$ is stabilized by resonance over two oxygen atoms,making it a weaker acid than $(x)$. $3.$ In $(z) CH_3OH$,the conjugate base $CH_3O^-$ has no resonance stabilization,making it the weakest acid. The order of acid strength is $x > y > z$. Since $pK_a$ is inversely proportional to acid strength $(pK_a = -\log K_a)$,the increasing order of $pK_a$ values is $x < y < z$.

Arrange the following in increasing order of their $pK_a$ values:
$(x) CH_3SO_3H$
$(y) CH_3COOH$
$(z) CH_3OH$

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Arrange the following in increasing order of their $pK_a$ values: $(x) CH_3SO_3H$ $(y) CH_3COOH$ $(z) CH_3OH$