Arrange the following in order of $C-Br$ bond strength in a polar solvent. The structures are as follows:
$(I)$ $1$-methylcyclohexa-$2,4$-dienyl bromide
$(II)$ cyclohexa-$2,4$-dienyl bromide
$(III)$ $1$-methylcyclopenta-$2,4$-dienyl bromide
$(IV)$ cyclopenta-$2,4$-dienyl bromide

What is the major product $Z$ in the given reaction sequence?
$(CH_3)_2 C=O \xrightarrow[(2) H_3O^{+}]{\text{(1) } C_2H_5MgBr} X$
$i) SOCl_2$ $\xrightarrow[\Delta]{\text{ii) } CH_3ONa} Y$ $\xrightarrow[\text{Peroxide}]{HBr} Z$

For the following compounds,the correct statement$(s)$ with respect to nucleophilic substitution reactions is(are):
$I$: Benzyl bromide $(C_6H_5CH_2Br)$
$II$: Cyclohexylmethyl bromide $(C_6H_{11}CH_2Br)$
$III$: tert-Butyl bromide $((CH_3)_3CBr)$
$IV$: $1-$Phenylethyl bromide $(C_6H_5CH(CH_3)Br)$
$A$. $I$ and $III$ follow $S_{N}1$ mechanism
$B$. $I$ and $II$ follow $S_{N}2$ mechanism
$C$. Compound $IV$ undergoes inversion of configuration
$D$. The order of reactivity for $I$,$III$ and $IV$ is: $IV > I > III$

$S_N^1$ reaction is faster in

The reaction of propylbenzene with bromine in the presence of light and heat gives ...................

Predict the product for the following reaction:
$\xrightarrow[\Delta]{alc. \ KOH}$ product