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(A) The displacement ability of a metal depends on its standard reduction potential $(E^{\circ})$. $A$ metal with a more negative $E^{\circ}$ value ac

Vedclass · Accepted Answer

$Mg > Al > Zn > Fe > Cu$

Vedclass · Answer

(A) The displacement ability of a metal depends on its standard reduction potential $(E^{\circ})$. $A$ metal with a more negative $E^{\circ}$ value acts as a stronger reducing agent and can displace a metal with a more positive $E^{\circ}$ value from its salt solution.The standard reduction potentials are:$E^{\circ} Mg^{+2}/Mg = -2.36 \ V$$E^{\circ} Al^{+3}/Al = -1.66 \ V$$E^{\circ} Zn^{+2}/Zn = -0.76 \ V$$E^{\circ} Fe^{+2}/Fe = -0.44 \ V$$E^{\circ} Cu^{+2}/Cu = +0.34 \ V$Since the reduction potential increases in the order $Mg  Al > Zn > Fe > Cu$.

Arrange the following metals in the order in which they displace each other from the solution of their salts: $Al, Cu, Fe, Mg$ and $Zn$.

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