(B) The $O-O$ bond length in $H_2O_2$ is $1.48 \ \mathring{A}$ (single bond).In $O_3$,the $O-O$ bond length is $1.28 \ \mathring{A}$ (due to resonance

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(B) The $O-O$ bond length in $H_2O_2$ is $1.48 \ \mathring{A}$ (single bond).In $O_3$,the $O-O$ bond length is $1.28 \ \mathring{A}$ (due to resonance,it has partial double bond character).In $O_2$,the $O-O$ bond length is $1.21 \ \mathring{A}$ (double bond).Therefore,the decreasing order of bond lengths is $H_2O_2 > O_3 > O_2$.

Class 11 Chemistry Chemical Bonding and Molecular Structure Mix Examples-Chemical Bonding

Medium

Arrange the following molecules according to the decreasing order of their $O-O$ bond lengths.

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A
$O_3 > H_2O_2 > O_2$
B
$H_2O_2 > O_3 > O_2$
C
$O_2 > H_2O_2 > O_3$
D
$O_2 > O_3 > H_2O_2$

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Chemical Bonding and Molecular Structure

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Mix Examples-Chemical Bonding

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Which of the following attractions is the strongest?

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Which of the following pairs does not contain isoelectronic species?

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Match List-$I$ with List-$II$:

List-$I$ List-$II$

$(P). \ IF_7$ $(a). \ \text{Planar} \ \& \ \text{Polar}$

$(Q). \ SO_2$ $(b). \ \text{Non-planar} \ \& \ \text{Polar}$

$(R). \ SF_4$ $(c). \ \text{Planar} \ \& \ \text{Non-polar}$

$(S). \ CS_2$ $(d). \ \text{Non-planar} \ \& \ \text{Non-polar}$

List-$I$	List-$II$
$(P). \ IF_7$	$(a). \ \text{Planar} \ \& \ \text{Polar}$
$(Q). \ SO_2$	$(b). \ \text{Non-planar} \ \& \ \text{Polar}$
$(R). \ SF_4$	$(c). \ \text{Planar} \ \& \ \text{Non-polar}$
$(S). \ CS_2$	$(d). \ \text{Non-planar} \ \& \ \text{Non-polar}$