Arrange the following polymers in increasing order of their intermolecular forces.
$(i)$ Nylon $6,6$,Buna$-S$,Polythene.
$(ii)$ Nylon $6$,Neoprene,Polyvinyl chloride.

(N/A) The intermolecular forces of attraction in polymers depend on their classification as elastomers,plastics,or fibres.
$1$. Elastomers (e.g.,Buna$-S$,Neoprene) have the weakest intermolecular forces.
$2$. Plastics (e.g.,Polythene,Polyvinyl chloride) have intermediate intermolecular forces.
$3$. Fibres (e.g.,Nylon $6,6$,Nylon $6$) have the strongest intermolecular forces due to strong hydrogen bonding.
Therefore,the increasing order is:
$(i)$ $\text{Buna-}S < \text{Polythene} < \text{Nylon } 6,6$
$(ii)$ $\text{Neoprene} < \text{Polyvinyl chloride} < \text{Nylon } 6$