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(C) To determine the pH order, we calculate the millimoles (mmol) of $H^+$ and $OH^-$ ions in each mixture:$A$. $Ca(OH)_2$ is a strong base. $OH^-$ mm

Vedclass · Accepted Answer

$C < B < A$

Vedclass · Answer

(C) To determine the pH order, we calculate the millimoles (mmol) of $H^+$ and $OH^-$ ions in each mixture:$A$. $Ca(OH)_2$ is a strong base. $OH^-$ mmol $= 10 	imes 0.2 	imes 2 = 4$. $HCl$ is a strong acid. $H^+$ mmol $= 25 	imes 0.1 = 2.5$. Excess $OH^- = 4 - 2.5 = 1.5 	ext{ mmol}$. The solution is basic, so pH $> 7$.$B$. $H_2SO_4$ is a strong acid. $H^+$ mmol $= 10 	imes 0.01 	imes 2 = 0.2$. $Ca(OH)_2$ is a strong base. $OH^-$ mmol $= 10 	imes 0.01 	imes 2 = 0.2$. Since $H^+$ mmol $= OH^-$ mmol, the solution is neutral, so pH $= 7$.$C$. $H_2SO_4$ is a strong acid. $H^+$ mmol $= 10 	imes 0.1 	imes 2 = 2$. $KOH$ is a strong base. $OH^-$ mmol $= 10 	imes 0.1 = 1$. Excess $H^+ = 2 - 1 = 1 	ext{ mmol}$. The solution is acidic, so pH $Comparing the pH values: $C$ (acidic) $< B$ (neutral) $< A$ (basic). Therefore, the increasing order is $C < B < A$.

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