Arrange the following wavelengths $(\lambda)$ of given emission lines of $H$ atoms in increasing order:
$(a) \ n = 3 \xrightarrow{\lambda_1} n = 1$
$(b) \ n = 12 \xrightarrow{\lambda_3} n = 10$
$(c) \ n = 5 \xrightarrow{\lambda_2} n = 3$
$(d) \ n = 22 \xrightarrow{\lambda_4} n = 20$
Choose the correct option.

• A
  $\lambda_4 < \lambda_3 < \lambda_2 < \lambda_1$
• B
  $\lambda_4 < \lambda_2 < \lambda_3 < \lambda_1$
• C
  $\lambda_1 < \lambda_2 < \lambda_3 < \lambda_4$
• D
  $\lambda_1 < \lambda_3 < \lambda_2 < \lambda_4$