Arrange the oxides CrO,CrO_3,and Cr_2O_3 in t | vedclass

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(A) The acidic strength of metal oxides increases with an increase in the oxidation state of the metal. Calculating the oxidation states of $Cr$ in th

Vedclass · Accepted Answer

$CrO_3 > Cr_2O_3 > CrO$

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(A) The acidic strength of metal oxides increases with an increase in the oxidation state of the metal. Calculating the oxidation states of $Cr$ in the given oxides: $1$. In $CrO$,the oxidation state of $Cr$ is $+2$. $2$. In $Cr_2O_3$,the oxidation state of $Cr$ is $+3$. $3$. In $CrO_3$,the oxidation state of $Cr$ is $+6$. Since the acidic character is directly proportional to the oxidation state,the order of acidic strength is: $CrO_3 (+6) > Cr_2O_3 (+3) > CrO (+2)$.

Arrange the oxides $CrO$,$CrO_3$,and $Cr_2O_3$ in the decreasing order of acidic strength.

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