Aruna has only Rs. 1 and Rs. 2 coins with her | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the number of $Rs. 1$ coins be $x$ and the number of $Rs. 2$ coins be $y$.According to the problem,the total number of coins is $50$,so $x + y

Vedclass · Accepted Answer

$25$ and $25$

Vedclass · Answer

(B) Let the number of $Rs. 1$ coins be $x$ and the number of $Rs. 2$ coins be $y$.According to the problem,the total number of coins is $50$,so $x + y = 50$ (Equation $i$).The total value of the money is $Rs. 75$,so $1x + 2y = 75$ (Equation $ii$).Subtracting Equation $i$ from Equation $ii$:$(x + 2y) - (x + y) = 75 - 50$$y = 25$.Substituting $y = 25$ into Equation $i$:$x + 25 = 50$$x = 25$.Therefore,the number of $Rs. 1$ coins is $25$ and the number of $Rs. 2$ coins is $25$.

Aruna has only $Rs. 1$ and $Rs. 2$ coins with her. If the total number of coins that she has is $50$ and the amount of money with her is $Rs. 75$,then the number of $Rs. 1$ and $Rs. 2$ coins are,respectively

Similar Questions

The solution set of the pair of equations $x = -2$ and $y = 3$ is:

Solve the following pair of equations by the cross-multiplication method:
$\frac{x}{a} + \frac{y}{b} = a + b$
$\frac{x}{a^2} + \frac{y}{b^2} = 2$

Do the following equations represent a pair of coincident lines? Justify your answer.
$-2x - 3y = 1$
$6y + 4x = -2$

For a two-digit number,if the sum of its digits is equal to the product of its digits,then the number is .............

For the pair of equations $\lambda x + 3y = -7$ and $2x + 6y = 14$ to have infinitely many solutions,the value of $\lambda$ should be $1$. Is the statement true? Give reasons.

Vedclass Test Series

Exam Paper Generator

Online Exam Module